Question

b. $(4x^{2}-3x + 5)-(3x^{2}-x - 8)$

Explanation:

Step1: Distribute the negative sign

$4x^2 - 3x + 5 - 3x^2 + x + 8$

Step2: Combine like $x^2$ terms

$(4x^2 - 3x^2) - 3x + x + 5 + 8 = x^2 - 3x + x + 5 + 8$

Step3: Combine like $x$ terms

$x^2 + (-3x + x) + 5 + 8 = x^2 - 2x + 5 + 8$

Step4: Combine constant terms

$x^2 - 2x + (5 + 8) = x^2 - 2x + 13$

Answer:

$x^2 - 2x + 13$