Question

b. $\frac{1}{4} + \frac{9}{8} = $
d. $\frac{4}{9} + \frac{4}{7} = $
f. $\frac{3}{4} + \frac{5}{6} = $

Explanation:

Step1: Find common denominator for b

The least common denominator of 4 and 8 is 8.
$\frac{1}{4} = \frac{1\times2}{4\times2} = \frac{2}{8}$

Step2: Add fractions for b

Add the numerators over the common denominator.
$\frac{2}{8} + \frac{9}{8} = \frac{2+9}{8} = \frac{11}{8}$

Step3: Find common denominator for d

The least common denominator of 9 and 7 is 63.
$\frac{4}{9} = \frac{4\times7}{9\times7} = \frac{28}{63}$, $\frac{4}{7} = \frac{4\times9}{7\times9} = \frac{36}{63}$

Step4: Add fractions for d

Add the numerators over the common denominator.
$\frac{28}{63} + \frac{36}{63} = \frac{28+36}{63} = \frac{64}{63}$

Step5: Find common denominator for f

The least common denominator of 4 and 6 is 12.
$\frac{3}{4} = \frac{3\times3}{4\times3} = \frac{9}{12}$, $\frac{5}{6} = \frac{5\times2}{6\times2} = \frac{10}{12}$

Step6: Add fractions for f

Add the numerators over the common denominator.
$\frac{9}{12} + \frac{10}{12} = \frac{9+10}{12} = \frac{19}{12}$

Answer:

b. $\frac{11}{8}$
d. $\frac{64}{63}$
f. $\frac{19}{12}$