Question

divide
$(28v^{3}+32v^{2}+16v)div(-4v)$

Explanation:

Step1: Split the polynomial division

$\frac{28v^3 + 32v^2 + 16v}{-4v} = \frac{28v^3}{-4v} + \frac{32v^2}{-4v} + \frac{16v}{-4v}$

Step2: Simplify each term

$\frac{28v^3}{-4v} = -7v^2$, $\frac{32v^2}{-4v} = -8v$, $\frac{16v}{-4v} = -4$

Step3: Combine simplified terms

$-7v^2 - 8v - 4$

Answer:

$-7v^2 - 8v - 4$