Question

let $h(x)=\frac{1}{x^{3}}-\frac{2}{x^{2}}$. $h(-1)=square$

Explanation:

Step1: Find the derivative of \(h(x)\)

Use the power - rule \((x^n)^\prime=nx^{n - 1}\). For \(h(x)=\frac{1}{3}x^{3}-\frac{1}{2}x^{2}\), then \(h^\prime(x)=x^{2}-x\).

Step2: Evaluate \(h^\prime(-1)\)

Substitute \(x = - 1\) into \(h^\prime(x)\). So \(h^\prime(-1)=(-1)^{2}-(-1)\).

Step3: Simplify the expression

\(h^\prime(-1)=1 + 1=2\).

Answer:

2