Question

$\log_{64}32$

Explanation:

Step1: Express bases as powers of 2

$64=2^6$, $32=2^5$

Step2: Rewrite log with new bases

$\log_{2^6} 2^5$

Step3: Apply log power rule

$\frac{5}{6}\log_{2}2$

Step4: Evaluate $\log_{2}2=1$

$\frac{5}{6} \times 1$

Answer:

$\frac{5}{6}$