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solve $-2x - 7 > x + 8$. a. $x < -3$ b. $x > -3$ c. $x < -5$ d. $x > -5$

Question

solve $-2x - 7 > x + 8$.

a. $x < -3$

b. $x > -3$

c. $x < -5$

d. $x > -5$

Explanation:

Step1: Isolate x terms

Add $2x$ to both sides:
$-7 > 3x + 8$

Step2: Isolate constant terms

Subtract 8 from both sides:
$-15 > 3x$

Step3: Solve for x

Divide by 3 (reverse inequality? No, positive divisor):
$\frac{-15}{3} > x$
$x < -5$

Answer:

C. $x < -5$