Question

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write the formula:

1. copper (ii) chlorate
2. calcium nitride
3. aluminum carbonate
4. potassium bromide
5. barium fluoride
6. cesium hydroxide

Explanation:

1. Copper (II) chlorate

Step1: Identify ions

Copper (II) ion: $Cu^{2+}$, Chlorate ion: $ClO_3^-$

Step2: Balance charges

To balance $2+$ and $1-$, need 2 chlorate ions. So formula: $Cu(ClO_3)_2$

Step1: Identify ions

Calcium ion: $Ca^{2+}$, Nitride ion: $N^{3-}$

Step2: Find LCM of charges (6)

Calcium: $6\div2 = 3$, Nitride: $6\div3 = 2$. Formula: $Ca_3N_2$

Step1: Identify ions

Aluminum ion: $Al^{3+}$, Carbonate ion: $CO_3^{2-}$

Step2: Balance charges

LCM of 3 and 2 is 6. Aluminum: $6\div3 = 2$, Carbonate: $6\div2 = 3$. Formula: $Al_2(CO_3)_3$

Answer:

$Cu(ClO_3)_2$

2. Calcium nitride