mother... a+ (homozygous for bloodtype and heterozygous for rh factor)
father... b- (heterozygous for bloodtype and homozygous for rh factor)
(value = 14 points)
a. what is the mother’s genotype for both bloodtype and rh factor?
b. what is the father’s genotype for both bloodtype and rh factor?
give both the genotypes and blood types in the chart below of any possible offspring.
male sperm cells
female egg cells
blood type?
blood type?
blood type?
blood type?
blood type?
blood type?
blood type?
blood type?
blood type?
blood type?
blood type?
blood type?
blood type?
blood type?
blood type?
blood type?
fill out the chart concerning the mathematical possibilities of the chart above.
fractional chance
% chance
a+
a-
b+
b-
ab+
ab-
o+
o-

Question

Accepted Answer

# Explanation:
## Step1: Determine mother's genotype
The mother is A+ homozygous for blood - type and heterozygous for Rh factor. For blood - type, the allele for A is $I^A$, and since she is homozygous, her blood - type genotype is $I^A I^A$. For Rh factor, the positive allele is $D$ and negative is $d$, and being heterozygous her Rh - factor genotype is $Dd$. So her overall genotype is $I^A I^A Dd$.
## Step2: Determine father's genotype
The father is B - heterozygous for blood - type and homozygous for Rh factor. For blood - type, the allele for B is $I^B$, and being heterozygous his blood - type genotype is $I^B i$. For Rh factor, being homozygous negative his genotype is $dd$. So his overall genotype is $I^B i dd$.
## Step3: Set up Punnett - square for blood - type
The mother can only produce eggs with $I^A$ allele for blood - type, and the father can produce sperm with either $I^B$ or $i$ alleles. The possible genotypes of offspring for blood - type are $I^A I^B$ and $I^A i$, corresponding to blood - types AB and A respectively.
## Step4: Set up Punnett - square for Rh factor
The mother can produce eggs with either $D$ or $d$ alleles, and the father can only produce sperm with $d$ alleles. The possible genotypes of offspring for Rh factor are $Dd$ (Rh positive) and $dd$ (Rh negative).
## Step5: Combine results
The possible genotypes and blood - types of offspring are:
| Female Egg Cells | Male Sperm Cells |
|---|---|
| $I^A D$ | $I^B d$ (AB+), $i d$ (A -) |
| $I^A d$ | $I^B d$ (AB -), $i d$ (A -) |

The fractional and percentage chances:
- A+: $\frac{1}{4}$, 25%
- A -: $\frac{1}{4}$, 25%
- B+: 0, 0%
- B -: 0, 0%
- AB+: $\frac{1}{4}$, 25%
- AB -: $\frac{1}{4}$, 25%
- O+: 0, 0%
- O -: 0, 0%

# Answer:
A. $I^A I^A Dd$
B. $I^B i dd$
| Female Egg Cells | Male Sperm Cells |
|---|---|
| $I^A D$ | $I^B d$ (AB+), $i d$ (A -) |
| $I^A d$ | $I^B d$ (AB -), $i d$ (A -) |
| Fractional Chance | A+: $\frac{1}{4}$, A -: $\frac{1}{4}$, B+: 0, B -: 0, AB+: $\frac{1}{4}$, AB -: $\frac{1}{4}$, O+: 0, O -: 0 |
| % Chance | A+: 25%, A -: 25%, B+: 0%, B -: 0%, AB+: 25%, AB -: 25%, O+: 0%, O -: 0% |

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QUESTION IMAGE

Question

Explanation:

Step1: Determine mother's genotype

Step2: Determine father's genotype

Step3: Set up Punnett - square for blood - type

Step4: Set up Punnett - square for Rh factor

Step5: Combine results

Answer:

Female Egg Cells	Male Sperm Cells
\(I^A d\)	\(I^B d\) (AB -), \(i d\) (A -)
Fractional Chance	A+: \(\frac{1}{4}\), A -: \(\frac{1}{4}\), B+: 0, B -: 0, AB+: \(\frac{1}{4}\), AB -: \(\frac{1}{4}\), O+: 0, O -: 0
% Chance	A+: 25%, A -: 25%, B+: 0%, B -: 0%, AB+: 25%, AB -: 25%, O+: 0%, O -: 0%