Question

2 multiple choice 1 point write $-5x + 15y = -30$ in slope - intercept form. $\bigcirc\\ y = \frac{1}{3}x + 2$ $\bigcirc\\ y = \frac{1}{3}x - 2$ $\bigcirc\\ y = -\frac{1}{3}x + 2$ $\bigcirc\\ y = -\frac{1}{3}x - 2$

Explanation:

Step1: Recall slope - intercept form

The slope - intercept form of a linear equation is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y - intercept. We need to solve the given equation \(-5x + 15y=-30\) for \(y\).

Step2: Isolate the term with \(y\)

Add \(5x\) to both sides of the equation \(-5x + 15y=-30\).
\[

$$\begin{align*} -5x+15y + 5x&=-30 + 5x\\ 15y&=5x-30 \end{align*}$$

\]

Step3: Solve for \(y\)

Divide each term in the equation \(15y = 5x-30\) by \(15\).
\[

$$\begin{align*} y&=\frac{5x}{15}-\frac{30}{15}\\ y&=\frac{1}{3}x - 2 \end{align*}$$

\]

Answer:

B. \(y=\frac{1}{3}x - 2\)