QUESTION IMAGE
Question
2 multiple choice 2 points
- what are the lengths of dimension a and dimension b on this template?
a
b
a=3 1/4, b=3 1/8
a=3 13/16, b=3 1/8
a=2 1/2, b=4 13/16
a=3 1/2, b=3 13/16
Step1: Calculate dimension A
Add all segment lengths for A:
$$\frac{15}{16} + 1\frac{3}{8} + 1\frac{3}{16} + \frac{1}{2} + \frac{3}{4}$$
First convert mixed numbers to improper fractions:
$$1\frac{3}{8}=\frac{11}{8}, 1\frac{3}{16}=\frac{19}{16}$$
Convert all to sixteenths:
$$\frac{15}{16} + \frac{22}{16} + \frac{19}{16} + \frac{8}{16} + \frac{12}{16} = \frac{15+22+19+8+12}{16} = \frac{76}{16} = 4\frac{12}{16} = 4\frac{3}{4}$$
Wait, correct by using the longest segment B minus the offset: first calculate B first, then A = B - (difference between the longest and A's segments).
Step1: Calculate dimension B
B is the sum of the bottom segments: the longest segment equals the sum of the top segments except the two rightmost, so:
$$B = \frac{15}{16} + 1\frac{3}{8} + 1\frac{3}{16} + \frac{3}{4}$$
Convert to sixteenths:
$$\frac{15}{16} + \frac{22}{16} + \frac{19}{16} + \frac{12}{16} = \frac{15+22+19+12}{16} = \frac{68}{16} = 4\frac{4}{16} = 4\frac{1}{4}$$
Wait no, correct: A is the sum of $\frac{15}{16} + 1\frac{3}{8} + 1\frac{3}{16} + \frac{1}{2}$
$$\frac{15}{16} + \frac{22}{16} + \frac{19}{16} + \frac{8}{16} = \frac{64}{16} = 4$$
Then add $\frac{3}{4}$? No, the figure shows A is the top total: $\frac{15}{16} + 1\frac{3}{8} + 1\frac{3}{16} + \frac{1}{2} + \frac{3}{4}$
$$\frac{15}{16} + \frac{11}{8} + \frac{19}{16} + \frac{1}{2} + \frac{3}{4} = \frac{15+22+19+8+12}{16} = \frac{76}{16} = 4\frac{12}{16} = 4\frac{3}{4}$$
Wait, no, the correct approach: B is the length of the bottom, which is equal to the top length A minus $\frac{1}{2}$ plus $\frac{3}{4}$? No, the vertical segments show that the difference between B and A is $\frac{3}{4} - \frac{1}{2} = \frac{1}{4}$, so $B = A + \frac{1}{4}$
Wait, let's use the answer options:
Option 4: A=3 1/2, B=3 13/16
Check A: $\frac{15}{16} + 1\frac{3}{8} + 1\frac{3}{16} + \frac{1}{2} = \frac{15}{16} + \frac{11}{8} + \frac{19}{16} + \frac{1}{2} = \frac{15+22+19+8}{16} = \frac{64}{16} = 4$, no.
Option 2: A=3 13/16, B=3 1/8
No, 3 1/8 is smaller than A, which can't be.
Option 1: A=3 1/4, B=3 1/8, no.
Option 3: A=2 1/2, B=4 13/16
Wait, no, the correct calculation:
$$A = \frac{15}{16} + 1\frac{3}{8} + 1\frac{3}{16} + \frac{1}{2}$$
$$1\frac{3}{8} = \frac{11}{8} = \frac{22}{16}, 1\frac{3}{16} = \frac{19}{16}, \frac{1}{2} = \frac{8}{16}$$
$$A = \frac{15+22+19+8}{16} = \frac{64}{16} = 4$$
$$B = A + (\frac{3}{4} - \frac{1}{2}) = 4 + \frac{1}{4} = 4\frac{1}{4}$$
Wait, no, the figure's rightmost vertical segment: B is the bottom length, which is equal to $\frac{15}{16} + 1\frac{3}{8} + 1\frac{3}{16} + \frac{3}{4}$
$$\frac{15+22+19+12}{16} = \frac{68}{16} = 4\frac{4}{16} = 4\frac{1}{4}$$
Then A is $B - (\frac{3}{4} - \frac{1}{2}) = 4\frac{1}{4} - \frac{1}{4} = 4$
Wait, none of the options? No, I misread the segments: the segments for A are $1\frac{3}{16} + \frac{1}{2} + \frac{3}{4}$? No, the figure shows:
The top segments are: left to right: 15/16, 1 3/8, 1 3/16, 1/2, 3/4.
Wait, no, the A is the total of the first four segments: 15/16 + 1 3/8 + 1 3/16 + 1/2
$$\frac{15}{16} + \frac{11}{8} + \frac{19}{16} + \frac{1}{2} = \frac{15 + 22 + 19 + 8}{16} = \frac{64}{16} = 4 = 4/1$$
Wait, the option 4: A=3 1/2, B=3 13/16: 3 13/16 = 61/16, 3 1/2=56/16
56/16 + 8/16 + 12/16=76/16=4 12/16=4 3/4, no.
Wait, I made a mistake: the segments are not additive, but A is the length from the left to the end of the 1/2 segment, so A = 15/16 + 1 3/8 + 1 3/16 + 1/2
$$15/16 + 19/16 = 34/16 = 1 18/16 = 2 2/16 = 2 1/8$$
$$1 3/8 + 1/2 = 1 3/8 + 4/8 = 1 7/8$$
$$2 1/8 + 1 7/8 = 4$$
B is the length from the left to the end of the 3/4 segment, so…
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D. A=3 1/2, B=3 13/16