Question

multiply and, if possible, simplify. assume that x is a nonnegative real number. $sqrt{34x^2} cdot sqrt{2x}$
$sqrt{34x^2} cdot sqrt{2x} = square$
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Explanation:

Step1: Combine square roots

$\sqrt{34x^2} \cdot \sqrt{2x} = \sqrt{34x^2 \cdot 2x}$

Step2: Multiply inside the root

$\sqrt{34 \cdot 2 \cdot x^2 \cdot x} = \sqrt{68x^3}$

Step3: Factor into perfect squares

$\sqrt{4 \cdot 17 \cdot x^2 \cdot x} = \sqrt{4x^2} \cdot \sqrt{17x}$

Step4: Simplify perfect square roots

$2x\sqrt{17x}$

Answer:

$2x\sqrt{17x}$