Question

e and f are mutually exclusive events. p(e) = 0.1; p(f) = 0.6. find p(e | f)

Explanation:

Step1: Recall the formula for conditional probability

The formula for conditional probability is $P(E|F)=\frac{P(E\cap F)}{P(F)}$.

Step2: Use the property of mutually - exclusive events

For mutually - exclusive events $E$ and $F$, $P(E\cap F) = 0$.

Step3: Calculate $P(E|F)$

Substitute $P(E\cap F)=0$ and $P(F) = 0.6$ into the conditional - probability formula: $P(E|F)=\frac{0}{0.6}=0$.

Answer:

0