QUESTION IMAGE
Question
name:date:per:sex-linked genetic punnett square problemsdirections: use the following information to answer the questions below:all are sex-linked recessive disorders.h= normal blood clottingh=hemophiliam= normalm= muscular dystrophyc=normal visionc= colorblind1. write the genotypes for the following individuals:a. female with no family history of hemophiliab. male with hemophiliac. male with muscular dystrophyd. male with normal color visione. normal color vision female with colorblind fatherf. male with normal blood clottingg. colorblind male2. cross a female who is a carrier of the gene for hemophilia with a man who has normal blood clotting. tell the expected phenotypic ratio of the offspring.3. cross a female with normal color vision, but whose father was colorblind, with a man who has colorblindness. tell the expected phenotypic ratio of the offspring.4. cross a woman who does not suffer from muscular dystrophy and has no family history of muscular dystrophy with a man who has the disorder. tell the expected phenotypic ratio of the offspring.
Step1: Correct Genotypes (Q1)
Sex-linked genes are on X; males have XY, females XX.
a. $X^H X^H$
b. $X^h Y$
c. $X^m Y$
d. $X^C Y$
e. $X^C X^c$
f. $X^H Y$
g. $X^c Y$
Step2: Solve Hemophilia Cross (Q2)
Carrier female $X^H X^h$ × Normal male $X^H Y$
Offspring genotypes: $X^H X^H$, $X^H Y$, $X^H X^h$, $X^h Y$
Phenotypes: Normal female, Normal male, Carrier female, Affected male
Step3: Solve Colorblind Cross (Q3)
Carrier female $X^C X^c$ × Colorblind male $X^c Y$
Offspring genotypes: $X^C X^c$, $X^C Y$, $X^c X^c$, $X^c Y$
Phenotypes: Carrier female, Normal male, Affected female, Affected male
Step4: Solve Muscular Dystrophy Cross (Q4)
Non-carrier female $X^M X^M$ × Affected male $X^m Y$
Offspring genotypes: $X^M X^m$, $X^M Y$
Phenotypes: Carrier female, Normal male
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
- Genotypes:
a. $X^H X^H$
b. $X^h Y$
c. $X^m Y$
d. $X^C Y$
e. $X^C X^c$
f. $X^H Y$
g. $X^c Y$
- Phenotypic ratio: 2 normal females (1 non-carrier, 1 carrier) : 1 normal male : 1 male with hemophilia, or simplified 1:1:1:1 for distinct phenotypes (normal female, carrier female, normal male, affected male)
- Phenotypic ratio: 1 carrier female : 1 normal male : 1 colorblind female : 1 colorblind male, or 1:1:1:1
- Phenotypic ratio: 1 carrier female : 1 normal male, or 1:1