Question

1. name the following molecules using iupac rules.

Explanation:

First Molecule (Alkene)

Step1: Find the longest carbon chain with the double bond.

The longest chain has 6 carbons (hexene). The double bond is at carbon 3. Substituents: ethyl at C - 3, methyl at C - 2.

Step2: Number the chain to give the double bond the lowest number, then list substituents alphabetically.

Name: 3 - ethyl - 2 - methyl - 3 - hexene

Second Molecule (Carboxylic Acid)

Step1: Identify the functional group (carboxylic acid, -COOH) and the longest carbon chain.

Longest chain: 5 carbons (pentanoic acid). No substituents.

Step2: Name based on the chain length and functional group.

Name: Pentanoic acid (or 1 - pentanoic acid, but usually pentanoic acid for straight - chain)

Third Molecule (Aldehyde)

Step1: Identify the functional group (aldehyde, -CHO) and the longest carbon chain.

Longest chain: 3 carbons (propanal). No substituents.

Step2: Name based on the chain length and functional group.

Name: Propanal

Answer:

• First Molecule: 3 - ethyl - 2 - methyl - 3 - hexene
• Second Molecule: Pentanoic acid
• Third Molecule: Propanal