Question

ng the inequality.

1. $-2x + 12 < -4$

$-2x + 12 - \underline{\quad\quad} < -4 - \underline{\quad\quad}$
$-2x < \underline{\quad\quad}$
$-2x \div \underline{\quad\quad} > \underline{\quad\quad} \div \underline{\quad\quad}$
$x > \underline{\quad\quad}$

Explanation:

Step1: Subtract 12 from both sides

$-2x + 12 - 12 < -4 - 12$

Step2: Simplify both sides

$-2x < -16$

Step3: Divide by -2 (reverse inequality)

$-2x \div (-2) > -16 \div (-2)$

Step4: Simplify to solve for x

$x > 8$

Answer:

Blanks filled in order: 12, 12, -16, (-2), -16, (-2), 8
Final solution: $x > 8$