Question

now, we factor and cancel common factors.
lim(x→ - 4⁻) (3x + 12)/-(x + 4)=lim(x→ - 4⁻) ((x + 4))/-(x + 4)
=lim(x→ - 4⁻)
=

Explanation:

Step1: Factor the numerator

Factor out 3 from $3x + 12$ to get $3(x + 4)$. So, $\lim_{x
ightarrow - 4^{-}}\frac{3x + 12}{-(x + 4)}=\lim_{x
ightarrow - 4^{-}}\frac{3(x + 4)}{-(x + 4)}$.

Step2: Cancel common factors

Cancel out the common factor $(x + 4)$ (since $x
eq - 4$ when taking the limit). We get $\lim_{x
ightarrow - 4^{-}}\frac{3(x + 4)}{-(x + 4)}=\lim_{x
ightarrow - 4^{-}}\frac{3}{-1}$.

Step3: Evaluate the limit

Since $\frac{3}{-1}=-3$, $\lim_{x
ightarrow - 4^{-}}\frac{3}{-1}=-3$.

Answer:

$-3$