Question

ordering 1 point predict the order of decreasing radius for germanium, cesium, bromine, potassium. largest atomic radius 1 cesium 2 potassium 3 germanium 4 bromine smallest atomic radius

Explanation:

Step1: Recall atomic radius trends

Atomic radius generally increases down a group (due to more electron shells) and decreases across a period (due to increased nuclear charge pulling electrons closer).

Step2: Identify positions of elements

• Cesium (Cs) and Potassium (K) are in Group 1 (alkali metals). Cs is below K, so \( r(\text{Cs}) > r(\text{K}) \).
• Germanium (Ge) is in Group 14, Period 4. Bromine (Br) is in Group 17, Period 4. Across Period 4, from Ge to Br, atomic radius decreases (nuclear charge increases), so \( r(\text{Ge}) > r(\text{Br}) \).
• Compare K (Group 1, Period 4) with Ge (Group 14, Period 4): K is to the left of Ge, so \( r(\text{K}) > r(\text{Ge}) \).

Step3: Order from largest to smallest

Combining trends: \( \text{Cs} > \text{K} > \text{Ge} > \text{Br} \).

Answer:

1. cesium
2. potassium
3. germanium
4. bromine