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ou could solve this equation. we need to get h alone on one sicn the ot…

Question

ou could solve this equation. we need to get h alone on one sicn the other side. since h is inside the parentheses on the left, vto rewrite the equation without parentheses. go for it. distribuou can think of this as (5h - 15) is being multiplied by \\(\frac{1}{5}\\). \\(\frac{1}{5}(5h - 15) = 9h + 9\\) \\(\square = 9h + 9\\)

Explanation:

Step1: Distribute $\frac{1}{5}$

Multiply $\frac{1}{5}$ with each term inside the parentheses: $\frac{1}{5} \times 5h - \frac{1}{5} \times 15$
$\frac{1}{5} \times 5h = h$, $\frac{1}{5} \times 15 = 3$
So we get $h - 3$

Answer:

$h - 3$