Question

part 3:

\

$$\begin{array}{r} 3.6 \\\\ - 5.2 \\\\ \\hline - 2.4 \\end{array}$$

\quad \boldsymbol{\times} \quad \

$$\begin{array}{r} \\overset{4}{5}.\\overset{1}{2} \\\\ - 3.6 \\\\ \\hline 1.6 \\end{array}$$

\quad \boldsymbol{\checkmark}

$3.6 - 5.2 = -1.6$

part 4: let’s solve some word problems

\

$$\begin{array}{|c|c|} \\hline \\text{decimal points lined up} & \\text{(incorrect) lining up the digits from the right side} \\\\ \\hline \\begin{array}{r} 12.5 \\\\ + 6.23 \\\\ \\hline 18.73 \\end{array}$$

\quad \boldsymbol{\checkmark} & \

$$\begin{array}{r} 12.5 \\\\ + 6.23 \\\\ \\hline 7.48 \\end{array}$$

\quad \boldsymbol{\times} \\\\
\hline
\end{array}

1. brenda and jenna saved up $81.75 and $45.25 respectively to buy a gift for mother’s day. how much money in all have the sisters set aside for the gift?

\\_\\_\\_\\_\\_\\_

1. miley buys an assorted box of chocolates that contains 18.61 ounces of dark chocolate and 37.23 ounces of milk chocolate. how much do the chocolates weigh in total?

Explanation:

Sub - question 1:

Step1: Identify the operation

We need to find the total money saved by Brenda and Jenna, so we use addition. Brenda saved $81.75 and Jenna saved $45.25. The formula for total money $T$ is $T = 81.75+45.25$.

Step2: Perform the addition

Add the two decimal numbers: $81.75 + 45.25=127.00$.

Step1: Identify the operation

To find the total weight of the chocolates, we add the weight of dark chocolate and milk chocolate. The weight of dark chocolate is 18.61 ounces and let's assume the weight of milk chocolate is 37.23 ounces (since the number seems to be cut off but following the pattern). The formula for total weight $W$ is $W=18.61 + 37.23$.

Step2: Perform the addition

Add the two decimal numbers: $18.61+37.23 = 55.84$.

Answer:

The sisters have set aside $\$127.00$ in total for the gift.

Sub - question 2: