Question

1. a particular atom or ion has an electron configuration of kr5s²4d¹⁰. what is the identity of the atom or ion? zn in⁺ pd²⁺ cd²⁺ clear all

Explanation:

Step1: Determine electrons in [Kr]

The electron - configuration of Kr is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}$, and it has 36 electrons.

Step2: Calculate total electrons

The given configuration is $[Kr]5s^{2}4d^{10}$. The number of additional electrons is $2 + 10=12$. So the total number of electrons is $36+12 = 48$.

Step3: Analyze each option

• Zn has 30 electrons.
• In has 49 electrons, and $In^{+}$ has 48 electrons.
• Pd has 46 electrons, and $Pd^{2 + }$ has 44 electrons.
• Cd has 48 electrons, and $Cd^{2+}$ has 46 electrons.

Answer:

In$^{+}$