Question

plot the point $(-3, 5)$ and identify the quadrant.
click on the graph to plot a point. click a point to delete it.

Explanation:

Step1: Recall quadrant rules

In a coordinate plane, quadrants are defined by the signs of \(x\) and \(y\) coordinates:

• Quadrant I: \(x>0\), \(y>0\)
• Quadrant II: \(x<0\), \(y>0\)
• Quadrant III: \(x<0\), \(y<0\)
• Quadrant IV: \(x>0\), \(y<0\)

Step2: Analyze the point \((-3, 5)\)

For the point \((-3, 5)\), the \(x\)-coordinate is \(-3\) (which is \(<0\)) and the \(y\)-coordinate is \(5\) (which is \(>0\)).

Step3: Identify the quadrant

Using the quadrant rules, since \(x<0\) and \(y>0\), the point \((-3, 5)\) lies in Quadrant II.

Answer:

To plot the point \((-3, 5)\): Start at the origin \((0,0)\), move 3 units to the left (because \(x = - 3\)) along the \(x\)-axis, then move 5 units up (because \(y=5\)) along the \(y\)-axis and mark the point. The point \((-3, 5)\) is in Quadrant II.