Question

(1 point)
co₂
nacl
h₂o
polar covalent ionic nonpolar covalent

Explanation:

Step1: Analyze CO₂

Carbon dioxide (\(CO_2\)) has a linear structure with two \(C = O\) bonds. The electronegativity difference between \(C\) and \(O\) creates polar bonds, but the symmetric linear arrangement makes the molecule's dipole moments cancel out. So \(CO_2\) has nonpolar covalent bonds.

Step2: Analyze NaCl

Sodium chloride (\(NaCl\)) is formed by the transfer of an electron from \(Na\) (a metal) to \(Cl\) (a non - metal). This results in the formation of \(Na^+\) and \(Cl^-\) ions, and the bond between them is an ionic bond.

Step3: Analyze H₂O

Water (\(H_2O\)) has a bent structure. The \(O - H\) bonds are polar (due to the electronegativity difference between \(O\) and \(H\)), and the bent structure means the dipole moments do not cancel out. So \(H_2O\) has polar covalent bonds.

Answer:

\(CO_2\) - nonpolar covalent; \(NaCl\) - ionic; \(H_2O\) - polar covalent