Question

point k is located at (-2, -5) on the coordinate plane. point k is reflected over the y - axis to create point k. point k is then reflected over the x - axis to create point k. what ordered pair describes the location of k? answer attempt 1 out of 2 k ( , )

Explanation:

Step1: Reflect over y - axis

To reflect a point \((x,y)\) over the \(y\) - axis, the rule is \((x,y)\to(-x,y)\). For point \(K(-2,-5)\), when we reflect it over the \(y\) - axis, the \(x\) - coordinate changes its sign and the \(y\) - coordinate remains the same. So, \(x=-2\) becomes \(x = 2\) and \(y=-5\) remains \(y=-5\). Thus, the coordinates of \(K'\) are \((2,-5)\).

Step2: Reflect over x - axis

To reflect a point \((x,y)\) over the \(x\) - axis, the rule is \((x,y)\to(x,-y)\). For point \(K'(2,-5)\), when we reflect it over the \(x\) - axis, the \(x\) - coordinate remains the same and the \(y\) - coordinate changes its sign. So, \(x = 2\) remains \(x = 2\) and \(y=-5\) becomes \(y = 5\). Thus, the coordinates of \(K''\) are \((2,5)\).

Answer:

\((2,5)\)