QUESTION IMAGE
Question
practice problem #2
background: clams were placed into various temperatures of water. use the information in the data table below in order to create a proper scientific graph and to answer the corresponding questions.
| water temperature (°c) | number of developing clams |
|---|---|
| 20 | 92 |
| 25 | 120 |
| 30 | 140 |
| 35 | 99 |
| 40 | 72 |
| 45 | 36 |
| 50 | 0 |
- what is the dependent variable?
- what is the independent variable?
- what is the optimum temperature for clam development?
- what is the mean number of clams per sample?
- approximately how many clams would be developing in 10 degree celsius water?
- what is it called when you make predictions about data not yet recorded, such as the prediction we made in question number 5?
Step1: Calculate the mean
Sum all the number of developing clams: $72 + 92+120 + 140+99+72+36+0=631$.
There are 8 data - points.
The mean formula is $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $n = 8$ and $\sum_{i=1}^{n}x_{i}=631$.
So, $\bar{x}=\frac{631}{8}=78.875\approx79$.
Step2: Analyze the optimum temperature
The optimum temperature is the one at which the number of developing clams is the highest. From the table, at $30^{\circ}C$, the number of developing clams is 140, which is the maximum value in the 'Number of Developing Clams' column.
Step3: Predict for 10 - degree Celsius water
Since the number of clams is decreasing as the temperature moves away from $30^{\circ}C$ in both directions and based on the trend in the data, we can make an estimate. As the temperature decreases from $15^{\circ}C$ (where there are 72 clams) to $10^{\circ}C$, we can assume a further decrease. A rough estimate could be 20 (this is an extrapolation based on the trend of the data).
Step4: Define the prediction term
Making predictions about data not yet recorded is called extrapolation.
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- Number of developing clams
- Water temperature
- $30^{\circ}C$
- 79
- 20
- Extrapolation