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practice word equations: name each of the compounds under the question.…

Question

practice word equations:
name each of the compounds under the question.
then, draw the lewis diagrams and balance. don’t forget the states of matter!

  1. sodium chloride and fluorine gas make sodium fluoride and chlorine gas.
  1. the combustion of methane: ch₄ plus oxygen releases carbon dioxide and water
  1. silver oxide (ag₂o) decomposes into silver metal and oxygen gas.

balancing chemical equations:
complete the following equations with the coefficients.

  1. __ kclo₃ → kcl + __ o₂
  1. __ pb(oh)₂ + hcl → h₂o + __ pbcl₂
  1. __ albr₃ + k₂so₄ → kbr + __ al₂(so₄)₃
  1. __ c₃h₈ + o₂ → co₂ + __ h₂o
  1. __ c₈h₁₈ + o₂ → co₂ + __ h₂o

remember:

  1. draw a line to separate the reactants and products.
  2. number the atoms present on each side.
  3. balance → (hint: metals first, then non metals, then o, then h last!)

don’t forget to check to see if you satisfied the law of conservation of mass!

Explanation:

Response
Problem 4:

Step1: Identify atoms

Reactants: K=1, Cl=1, O=3; Products: K=1, Cl=1, O=2.

Step2: Balance O

Find LCM of 3 and 2, which is 6. So multiply \( KClO_3 \) by 2, \( O_2 \) by 3.
\( 2KClO_3
ightarrow KCl + 3O_2 \)

Step3: Balance K and Cl

Multiply \( KCl \) by 2.
\( 2KClO_3
ightarrow 2KCl + 3O_2 \)

Step1: Identify atoms

Reactants: Pb=1, O=2, H=3, Cl=1; Products: H=2, O=1, Pb=1, Cl=2.

Step2: Balance Cl

Multiply \( HCl \) by 2.
\( Pb(OH)_2 + 2HCl
ightarrow H_2O + PbCl_2 \)

Step3: Balance H and O

Now H: 2 + 2 = 4, O: 2. Products: H in \( H_2O \) should be 4, so multiply \( H_2O \) by 2.
\( Pb(OH)_2 + 2HCl
ightarrow 2H_2O + PbCl_2 \)

Step1: Identify atoms

Reactants: Al=1, Br=3, K=2, S=1, O=4; Products: K=1, Br=1, Al=2, S=3, O=12.

Step2: Balance Al

Multiply \( AlBr_3 \) by 2.
\( 2AlBr_3 + K_2SO_4
ightarrow KBr + Al_2(SO_4)_3 \)

Step3: Balance SO₄²⁻

Multiply \( K_2SO_4 \) by 3.
\( 2AlBr_3 + 3K_2SO_4
ightarrow KBr + Al_2(SO_4)_3 \)

Step4: Balance K and Br

Multiply \( KBr \) by 6.
\( 2AlBr_3 + 3K_2SO_4
ightarrow 6KBr + Al_2(SO_4)_3 \)

Answer:

2, 2, 3

Problem 5: