Question

pre-lab 1 question 8 4.75 points homework • answered • due today, 1:30 pm consider a solid object that is a rectangular - shaped block with a length of 5.00 cm, a width of 2.50 cm, a height of 1.00 cm. this solid object s mass is determined to have a mass of 33.8 g. please calculate the density of this solid object (to the correct significant figures). select an answer and submit. for keyboard navigation, use the up/down arrow keys to select an answer. a 0.370 g/cm³ b 2.70 g/cm³ c 2.704 g/cm³ d 12.5 g/cm3

Explanation:

Step1: Calculate the volume of the rectangular block

The formula for the volume \( V \) of a rectangular block is \( V = length \times width \times height \).
Given \( length = 5.00 \, \text{cm} \), \( width = 2.50 \, \text{cm} \), \( height = 1.00 \, \text{cm} \).
So, \( V = 5.00 \times 2.50 \times 1.00 = 12.5 \, \text{cm}^3 \).

Step2: Calculate the density

The formula for density \(
ho \) is \(
ho = \frac{mass}{volume} \).
Given \( mass = 33.8 \, \text{g} \), \( volume = 12.5 \, \text{cm}^3 \).
So, \(
ho = \frac{33.8}{12.5} = 2.704 \, \text{g/cm}^3 \). But we need to consider significant figures. The mass has 3 significant figures, and the volume (from multiplication of 5.00, 2.50, 1.00 which have 3, 3, 3 significant figures respectively) has 3 significant figures. When dividing, the result should have 3 significant figures. So, \( 2.704 \) rounded to 3 significant figures is \( 2.70 \, \text{g/cm}^3 \).

Answer:

b. 2.70 g/cm³