Question

problem 8
here is how haru tried to solve this system of equations.
did haru solve the system of equations correctly?
yes no
haru
$\

$$\begin{cases} y = -3x + 1 \\\\ x = 4 \\end{cases}$$

$
$-3x + 1 = 4$
$-3x = 3$
$x = -1$
$y = -3(-1) + 1$
$y = 4$
solution: $(-1, 4)$

Explanation:

Step1: Identify given system

The system is

$$\begin{cases} y = -3x + 1 \\ x = 4 \end{cases}$$

Step2: Substitute $x=4$ into $y$

Substitute $x=4$ into $y=-3x+1$:
$y = -3(4) + 1 = -12 + 1 = -11$

Step3: Analyze Haru's error

Haru incorrectly set $-3x+1=4$ instead of using the given $x=4$.

Answer:

No
The correct solution is $(4, -11)$, so Haru did not solve the system correctly.