Question

a programmer uses a 6 - bit computer system and writes a program that multiplies 8×9. which type of error would this cause? (2 points) round - off logical overflow arithmetic

Explanation:

In a 6 - bit computer system, the maximum positive integer that can be represented in unsigned form is \(2^{6}-1 = 63\). Since \(8\times9=72\) which is greater than 63, the result cannot be stored within the 6 - bit range, causing an overflow error.

Answer:

C. Overflow