Question

question 3 of 10
which point is a solution to $y \leq 3x - 4$?
\bigcirc a. $(0,0)$
\bigcirc b. $(3,1)$
\bigcirc c. $(-2,0)$
\bigcirc d. $(0,4)$

Explanation:

Step1: Test point A (0,0)

Substitute \(x = 0\), \(y = 0\) into \(y\leq3x - 4\):
\(0\leq3(0)-4\)
\(0\leq - 4\)
This is false.

Step2: Test point B (3,1)

Substitute \(x = 3\), \(y = 1\) into \(y\leq3x - 4\):
\(1\leq3(3)-4\)
\(1\leq9 - 4\)
\(1\leq5\)
This is true.

Step3: Test point C (-2,0)

Substitute \(x=-2\), \(y = 0\) into \(y\leq3x - 4\):
\(0\leq3(-2)-4\)
\(0\leq - 6 - 4\)
\(0\leq - 10\)
This is false.

Step4: Test point D (0,4)

Substitute \(x = 0\), \(y = 4\) into \(y\leq3x - 4\):
\(4\leq3(0)-4\)
\(4\leq - 4\)
This is false.

Answer:

B. (3, 1)