Question

question 12
blank 1×10^blank 2 atoms are found in a sample contains 2.54 grams of c6h12o6.

Explanation:

Step1: Calculate molar mass of $C_6H_{12}O_6$

The molar mass of carbon ($C$) is approximately $12.01\ g/mol$, hydrogen ($H$) is approximately $1.01\ g/mol$ and oxygen ($O$) is approximately $16.00\ g/mol$.
$M = 6\times12.01+12\times1.01 + 6\times16.00=180.18\ g/mol$

Step2: Calculate number of moles of $C_6H_{12}O_6$

$n=\frac{m}{M}$, where $m = 2.54\ g$ and $M = 180.18\ g/mol$.
$n=\frac{2.54}{180.18}\approx0.0141\ mol$

Step3: Calculate number of molecules of $C_6H_{12}O_6$

Using Avogadro's number $N_A=6.022\times 10^{23}\ molecules/mol$.
The number of molecules $N = n\times N_A=0.0141\times6.022\times 10^{23}\approx8.49\times 10^{21}\ molecules$

Step4: Calculate number of atoms in $C_6H_{12}O_6$

One molecule of $C_6H_{12}O_6$ has $6 + 12+6=24$ atoms.
The total number of atoms $N_{total}=N\times24=8.49\times 10^{21}\times24 = 2.04\times10^{23}$ atoms.

Answer:

Blank 1: 2.04
Blank 2: 23