Question

question 12 (multiple choice worth 1 points) (02.06r mc) the diagonals of parallelogram qrst intersect at point u. if tu = 6x - 5 and ru = 2x + 11, what is ru? 2 4 19 22

Explanation:

Step1: Recall parallelogram property

In a parallelogram, the diagonals bisect each other. So, $TU = RU$.

Step2: Set up the equation

Set $6x - 5=2x + 11$.

Step3: Solve for x

Subtract $2x$ from both sides: $6x-2x - 5=2x-2x + 11$, which simplifies to $4x-5 = 11$. Then add 5 to both sides: $4x-5 + 5=11 + 5$, getting $4x=16$. Divide both sides by 4: $x = 4$.

Step4: Find RU

Substitute $x = 4$ into the expression for $RU$. $RU=2x + 11=2\times4+11=8 + 11=19$.

Answer:

19