Question

question 20 (1 point) raising the temperature of 25 l of helium in a constant - pressure container from 100°c to 200°c. reduces the volume. has no effect on the volume. changes the volume to 473/373 x 25 l. increases the volume to 200/100 x 25 l.

Explanation:

Step1: Recall Charles's Law

At constant pressure, $V_1/T_1 = V_2/T_2$, where $V$ is volume and $T$ is temperature in Kelvin. Initial temperature $T_1=100 + 273=373K$, final temperature $T_2=200 + 273 = 473K$, and initial volume $V_1 = 25L$.

Step2: Solve for final volume $V_2$

From $V_1/T_1=V_2/T_2$, we can get $V_2=\frac{T_2}{T_1}\times V_1=\frac{473}{373}\times25L$. As temperature increases at constant - pressure, volume increases.

Answer:

Increases the volume to 473/373 x 25 L