Question

question 20 (0.5 points) give the formula from the systematic name vanadium (iv) hydroxide 1 2 a. v2 b. v c. v4 d. (cn)2 e. so3 f. (so3)2 g. (c2h3o2)2 h. c2h3o2 i. hso3 j. c2 k. c3 l. po3 m. hpo3 n. h2po3 o. oh p. (oh)2 q. s r. so4 i s. (oh)4 t. vanesa

Explanation:

Step1: Determine vanadium ion charge

Vanadium (IV) has a charge of +4, represented as $V^{4 +}$.

Step2: Determine hydroxide ion charge

Hydroxide ion is $OH^-$, with a charge of - 1.

Step3: Balance charges

To balance the +4 charge of vanadium, we need 4 hydroxide ions. So the formula is $V(OH)_4$.

Answer:

B. V, S. $(OH)_4$