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distribute $-3\left(3 - 2x^{2}\
ight)$.
Step1: Apply distributive property
The distributive property states that \(a(b + c)=ab+ac\). Here, \(a = - 3\), \(b = 3\) and \(c=-2x^{2}\). So we have \(-3\times3+(-3)\times(-2x^{2})\).
Step2: Calculate each term
Calculate \(-3\times3=-9\) and \((-3)\times(-2x^{2}) = 6x^{2}\).
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\(-9 + 6x^{2}\)