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in \\(\triangle pqr\\), \\(m\angle p = (4x + 14)\degree\\), \\(m\angle q = (x + 16)\degree\\), and \\(m\angle r = (3x - 2)\degree\\). what is the value of \\(x\\)?
answer attempt 1 out of 2
\\(x = \\)
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Step1: Recall triangle angle sum
The sum of angles in a triangle is \(180^\circ\). So, \(m\angle P + m\angle Q + m\angle R = 180^\circ\).
Step2: Substitute angle expressions
Substitute \(m\angle P=(4x + 14)^\circ\), \(m\angle Q=(x + 16)^\circ\), and \(m\angle R=(3x - 2)^\circ\) into the equation:
\[
(4x + 14)+(x + 16)+(3x - 2)=180
\]
Step3: Combine like terms
Combine the \(x\)-terms and constant terms:
\[
4x+x+3x + 14+16 - 2=180\\
8x + 28=180
\]
Step4: Solve for \(x\)
Subtract 28 from both sides:
\[
8x=180 - 28\\
8x=152
\]
Divide both sides by 8:
\[
x=\frac{152}{8}=19
\]
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\(19\)