Question

question
express in simplest radical form.
\\( xsqrt3{48x^{11}y^6} \\)
answer attempt 2 out of 2

Explanation:

Step1: Factor the radicand

$x\sqrt[3]{8 \cdot 6 \cdot x^9 \cdot x^2 \cdot y^6}$

Step2: Extract perfect cubes

$x \cdot \sqrt[3]{8} \cdot \sqrt[3]{x^9} \cdot \sqrt[3]{y^6} \cdot \sqrt[3]{6x^2}$

Step3: Simplify perfect cube roots

$x \cdot 2 \cdot x^3 \cdot y^2 \cdot \sqrt[3]{6x^2}$

Step4: Multiply like terms

$2x^{1+3}y^2\sqrt[3]{6x^2}$

Answer:

$2x^4y^2\sqrt[3]{6x^2}$