Question

question find the area of the figure below, composed of a rectangle with a semicircle removed from it. round to the nearest tenths place. answer attempt 1 out of 2

Explanation:

Step1: Calcular área del rectángulo

$A_{rectángulo}=l\times w = 9\times6=54$

Step2: Calcular radio del semicírculo

El diámetro del semicírculo es 6, entonces el radio $r = \frac{6}{2}=3$

Step3: Calcular área del semicírculo

$A_{semicírculo}=\frac{1}{2}\pi r^{2}=\frac{1}{2}\pi\times3^{2}=\frac{9\pi}{2}\approx14.1$

Step4: Calcular área del figura

$A = A_{rectángulo}-A_{semicírculo}=54 - 14.1 = 39.9$

Answer:

$39.9$