Question

question
find the distance between the two points rounding to the nearest tenth (if necessary)
(0, 7) and (-6, 3)

Explanation:

Step1: Identify distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.

Step2: Assign values

Let $(x_1,y_1)=(0,7)$ and $(x_2,y_2)=(-6,3)$. Then $x_2 - x_1=-6 - 0=-6$ and $y_2 - y_1=3 - 7=-4$.

Step3: Calculate squares

$(x_2 - x_1)^2=(-6)^2 = 36$ and $(y_2 - y_1)^2=(-4)^2 = 16$.

Step4: Sum squares

$(x_2 - x_1)^2+(y_2 - y_1)^2=36 + 16=52$.

Step5: Calculate distance

$d=\sqrt{52}\approx7.2$.

Answer:

$7.2$