Question

question
find the positive solution of the equation.
$6x^8 + 11 = 1547$
answer

Explanation:

Step1: Isolate the variable term

Subtract 11 from both sides.
$6x^3 = 1547 - 11$
$6x^3 = 1536$

Step2: Solve for $x^3$

Divide both sides by 6.
$x^3 = \frac{1536}{6}$
$x^3 = 256$

Step3: Find positive $x$

Take cube root of 256.
$x = \sqrt[3]{256} = \sqrt[3]{64 \times 4} = 4\sqrt[3]{4} \text{ or } 4 \times 4^{1/3} = 2^{8/3}$
(Alternatively, in decimal form: $x \approx 6.3496$)

Answer:

$4\sqrt[3]{4}$ (or approximately $6.35$)