Question

question 5 (1 point)
a car travels 90 km/h. how long does it take for it to travel 400 km?
4.1 h
4.2 h
4.3 h
4.4 h
question 6 (1 point)
suppose that an object travels from one point in space to another. make a comparison between the displacement and the distance traveled.
the displacement is either greater than or equal to the distance traveled.
the displacement is always equal to the distance traveled.
the displacement is either less than or equal to the distance traveled.
the displacement can be either greater than, smaller than, or equal to the distance traveled.

Explanation:

Question 5

Step1: Recall the formula for time

The formula relating speed (\(v\)), distance (\(d\)) and time (\(t\)) is \(t=\frac{d}{v}\).

Step2: Substitute the given values

Here, \(d = 400\space km\) and \(v=90\space km/h\). So, \(t=\frac{400}{90}\approx4.44\space h\)? Wait, no, wait, let's calculate \(\frac{400}{90}=\frac{40}{9}\approx4.44\)? But the options are 4.1,4.2,4.3,4.4. Wait, maybe I miscalculated. Wait, \(90\times4.4 = 396\), \(90\times4.44 = 399.6\approx400\). Wait, the options have 4.4. Let's check: \(t=\frac{400}{90}=\frac{40}{9}\approx4.44\), but the closest option is 4.4 h. Wait, maybe the problem expects \(\frac{400}{90}\approx4.4\) (rounding to one decimal place). So the calculation is \(t=\frac{d}{v}=\frac{400}{90}\approx4.4\space h\).

Distance is the total path length traveled, while displacement is the straight - line distance from the initial to the final position. In a straight - line motion without change in direction, distance and displacement are equal. In any other motion (with turns), the distance traveled (path length) is greater than the displacement (straight - line between start and end). So displacement is either less than or equal to the distance traveled.

Answer:

4.4 h (the option: 4.4 h)

Question 6