Question

question 6. 1 point what is t(x) when t(x)=7e^{x - 8}? select the correct answer below: o t(x)=7e^{x - 8} o t(x)=-56x^{-9}e^{x - 8} o t(x)=-56e^{x - 9} o t(x)=-56x^{-8}e^{x - 8}

Explanation:

Step1: Apply product - rule for differentiation

If $y = uv$, where $u = 7$ and $v=e^{x - 8}$, and the product - rule is $(uv)'=u'v + uv'$. Since $u = 7$, $u'=0$, and $v = e^{x - 8}$, $v'=e^{x - 8}$. Then $t'(x)=(7e^{x - 8})'=7e^{x - 8}$.

Answer:

$t'(x)=7e^{x - 8}$