Question

question 7 (2 points)
(02.07 mc)
a 3.2 - kg object is being pulled upward with a force of 45 n. its weight of 31 n opposes the upward force. what is the acceleration of the object?
○ a 4.4 m/s²
○ b 9.7 m/s²
○ c 12 m/s²
○ d 14 m/s²

Explanation:

Step1: Calculate net force

The upward force is $F_{up}=45\ N$ and the downward - weight is $F_{down}=31\ N$. The net force $F_{net}$ is given by $F_{net}=F_{up}-F_{down}$. So, $F_{net}=45 - 31=14\ N$.

Step2: Use Newton's second law

Newton's second law is $F = ma$, where $F$ is the net force, $m$ is the mass and $a$ is the acceleration. We know $F_{net}=14\ N$ and $m = 3.2\ kg$. Rearranging for $a$, we get $a=\frac{F_{net}}{m}$. So, $a=\frac{14}{3.2}\approx4.4\ m/s^{2}$.

Answer:

A. $4.4\ m/s^{2}$