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question 2 points 1 the perimeter of a rectangle is 290 cm and the leng…

Question

question 2 points 1 the perimeter of a rectangle is 290 cm and the length is 100 cm. find the width of the rectangle. 45 cm 65 cm 75 cm 95 cm

Explanation:

Step1: Recall the perimeter formula of a rectangle

The perimeter \( P \) of a rectangle is given by the formula \( P = 2\times (l + w) \), where \( l \) is the length and \( w \) is the width. We know \( P = 290 \) cm and \( l = 100 \) cm. Substitute these values into the formula: \( 290 = 2\times(100 + w) \).

Step2: Solve for \( w \)

First, divide both sides of the equation by 2: \( \frac{290}{2}=100 + w \), which simplifies to \( 145 = 100 + w \). Then, subtract 100 from both sides: \( w = 145 - 100 \).

Step3: Calculate the width

\( w = 45 \) cm.

Answer:

A. 45 cm