Question

question 3 (2 points)
what is the % cl in the compound c₅h₁₀ocl₂?
45.14 % cl
22.57 % cl
38.24 % cl
20.00 % cl

Explanation:

Step1: Calculate molar mass of each element in the compound

The molar mass of C is 12.01 g/mol, H is 1.01 g/mol, O is 16.00 g/mol, and Cl is 35.45 g/mol. For \(C_5H_{10}OCl_2\), the molar - mass of carbon in the compound is \(5\times12.01 = 60.05\) g/mol, hydrogen is \(10\times1.01=10.10\) g/mol, oxygen is 16.00 g/mol, and chlorine is \(2\times35.45 = 70.90\) g/mol.

Step2: Calculate the molar mass of the compound

The molar mass of \(C_5H_{10}OCl_2\) is \(M = 60.05+10.10 + 16.00+70.90=157.05\) g/mol.

Step3: Calculate the percentage of Cl

The percentage of Cl in the compound is \(\text{Percent of Cl}=\frac{\text{Mass of Cl in compound}}{\text{Molar mass of compound}}\times100\%=\frac{70.90}{157.05}\times100\%\approx45.14\%\)

Answer:

45.14 % Cl