Question

question 1 (2 points)
what is the oxidation number of p in h₃po₄?
+5
+3
+1
0
+7

Explanation:

Step1: Recall oxidation - number rules

In a neutral compound, the sum of oxidation numbers of all atoms is 0. Hydrogen ($H$) usually has an oxidation number of +1, and oxygen ($O$) usually has an oxidation number of -2.

Step2: Set up an equation

Let the oxidation number of $P$ be $x$. In $H_3PO_4$, we have 3 hydrogen atoms, 1 phosphorus atom, and 4 oxygen atoms. So the equation based on the sum - of - oxidation - numbers rule is: $3\times(+1)+x + 4\times(-2)=0$.

Step3: Solve the equation

First, simplify the left - hand side of the equation: $3 + x-8 = 0$. Then, combine like terms: $x-5 = 0$. Finally, solve for $x$: $x = + 5$.

Answer:

+5