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Question
question 2 (2 points) when the following equation is balanced, what is the coefficient in front of h₂o? fe₂o₃ (s) + h₂so₄ (aq) → fe₂(so₄)₃ (aq)
Step1: Balance sulfate ions
There are 3 sulfate ($SO_4$) groups in $Fe_2(SO_4)_3$, so we need 3 moles of $H_2SO_4$.
$Fe_2O_3(s)+3H_2SO_4(aq)
ightarrow Fe_2(SO_4)_3(aq)$
Step2: Balance hydrogen and oxygen
On the left - hand side, from $3H_2SO_4$, we have 6 hydrogen atoms. On the right - hand side, we need to form water. Also, considering the oxygen atoms, the balanced equation is $Fe_2O_3(s)+3H_2SO_4(aq)
ightarrow Fe_2(SO_4)_3(aq) + 3H_2O(l)$.
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