Question

question 1
0.5 pts
find the x - coordinate of the vertex for the graph of the equation
$y = -2x^2 + 8x - 1$
4
2
-2
-4

Explanation:

Step1: Recall vertex formula

For a quadratic equation \( y = ax^2 + bx + c \), the x - coordinate of the vertex is given by \( x=-\frac{b}{2a} \).

Step2: Identify a and b

In the equation \( y=-2x^{2}+8x - 1 \), we have \( a=-2 \) and \( b = 8 \).

Step3: Substitute into formula

Substitute \( a=-2 \) and \( b = 8 \) into the formula \( x =-\frac{b}{2a} \). So \( x=-\frac{8}{2\times(-2)} \).
First, calculate the denominator: \( 2\times(-2)=-4 \). Then, \( x =-\frac{8}{-4}=2 \).

Answer:

2