Question

question 3
1 pts
what is the molarity when 24 grams of lioh is added to 200 ml of water?
2 m
0.5 m
5 m
0.2 m
question 4
1 pts
how many grams of lioh are needed to make 100 ml of a 0.1 m solution?
0.002 grams
2 grams
0.2 grams
0.02 grams

Explanation:

Question 3

Step1: Calculate molar mass of LiOH

Molar mass of Li (6.94 g/mol) + O (16.00 g/mol) + H (1.01 g/mol) = 6.94 + 16.00 + 1.01 = 23.95 g/mol (approx 24 g/mol)

Step2: Find moles of LiOH

Moles = mass / molar mass = 24 g / 24 g/mol = 1 mol

Step3: Convert volume to liters

200 mL = 200 / 1000 = 0.2 L

Step4: Calculate molarity

Molarity (M) = moles / volume (L) = 1 mol / 0.2 L = 5 M

Step1: Convert volume to liters

100 mL = 100 / 1000 = 0.1 L

Step2: Find moles of LiOH

Moles = Molarity × Volume = 0.1 M × 0.1 L = 0.01 mol

Step3: Calculate mass of LiOH

Molar mass of LiOH ≈ 24 g/mol (from Q3). Mass = moles × molar mass = 0.01 mol × 24 g/mol = 0.24 g (approx 0.2 g considering rounding)

Answer:

C. 5 M

Question 4