Question

quiz 3.3.1 - solving quadratics
value: 1
solve
$(x - 5)^2 = 1$
a. x=4 or x=6
b. x=-6 or x=-4
c. x=-6 or x=4
d. x=-4 or x=6

Explanation:

Step1: Take square roots of both sides

$x-5 = \pm\sqrt{1}$

Step2: Simplify the square root

$x-5 = \pm1$

Step3: Solve for x (positive case)

$x = 5 + 1 = 6$

Step4: Solve for x (negative case)

$x = 5 - 1 = 4$

Answer:

a. x=4 or x=6