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the radius of a cylindrical construction pipe is 2 ft. if the pipe is 2…

Question

the radius of a cylindrical construction pipe is 2 ft. if the pipe is 22 ft long, what is its volume? use the value 3.14 for π, and round your answer to the nearest whole number. be sure to include the correct unit in your answer.

Explanation:

Step1: Recall cylinder volume formula

The volume of a cylinder is $V = \pi r^2 h$, where $r$ is radius, $h$ is height/length.

Step2: Substitute given values

$r=2$ ft, $h=22$ ft, $\pi=3.14$
$V = 3.14 \times (2)^2 \times 22$

Step3: Calculate step-by-step

First compute $2^2=4$, then $3.14 \times 4 = 12.56$, then $12.56 \times 22 = 276.32$

Step4: Round to nearest whole number

$276.32 \approx 276$, unit is cubic feet ($ft^3$)

Answer:

276 ft³